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Em uma loja de doces as caixas de bombons foram organizada em filas.o número de caixas por filas corresponde ao quadrado de um número adicionado ao seu quituplo,obtendo-se o número 36. qual é esse numero ??


Respostas

Primeiro, o quadrado de um número "x", o quadrado seria esse número elevado a potência "2", assim, x^2, adicionado (mais) o quíntuplo desse número, ou seja, 5 vezes "x", 5x, é igual a 36, temos: 
x^2 + 5x = 36 
x^2 + 5x - 36 = 0 [o 36 passa com sinal trocado] 
Temos uma expressão de 2º grau, para fazê-la, fórmula de Baskar: 
Delta = b^2 - 4 . a . c 
Onde: 
"a" é o termo que acompanha "x^2" 
"b" é o termo que acompanha "x" 
"c" é o número sozinho não acompanha ninguém, assim, na expressão: "x^2 + 5x - 36 = 0" temos: 
a = 1 
b = 5 
c = -36 
Na fórmula: 
Delta = b^2 - 4 . a . c 
Delta = 5^2 - 4 . 1 . (-36) 
Delta = 25 - 4 . (-36) 
Delta = 25 + 144 [jogo de sinal, - com - é +] 
Delta = 169 
Então temos dois valores para as caixas: 
x = -b + ou - raiz de Delta : 2 . a 
x = - 5 + ou - raiz de 169 : 2 . 1 
x = (- 5 + ou - 13) : 2 
Temos dois valores para "x": 
x1 = (-5 + 13) : 2 
x1 = + 8 : 2 
x1 = 4 
------------ 
x2 = (-5 - 13) : 2 
x2 = - 18 : 2 
x2 = -9 
Os possíveis valores para "x" é 4, e -9, porém estamos tratando de caixas por fila, não há caixas negativas, lógico, então só nos reta o +4. 
Resposta: Temos 4 caixas em cada fila. 


(em uma loja as caixas de um produto estavam organizadas em um arranjo piramidal)



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